4(x-1/2)^2-3x+1=2x+3)^2-19x+2

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Solution for 4(x-1/2)^2-3x+1=2x+3)^2-19x+2 equation: 



4(x-1/2)^2-3x+1=2x+3)^2-19x+2

We move all terms to the left:

4(x-1/2)^2-3x+1-(2x+3)^2-19x+2)=0

We add all the numbers together, and all the variables

4(+x-1/2)^2-3x-(2x+3)^2-19x+1+2)=0

We add all the numbers together, and all the variables

-22x+4(+x-1/2)^2-(2x+3)^2=0

We multiply all the terms by the denominator


-22x*2)^2+4(+x-((2x+3)^2)*2)^2-1=0

We add all the numbers together, and all the variables

x-22x*2)^2+4(-((2x+3)^2)*2)^2-1=0

Wy multiply elements

-44x^2+x-((2x+3)^2)*2)^2-1=0

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